2x+12=10-x^2

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Solution for 2x+12=10-x^2 equation: 



2x+12=10-x^2

We move all terms to the left:

2x+12-(10-x^2)=0

We get rid of parentheses

x^2+2x-10+12=0

We add all the numbers together, and all the variables

x^2+2x+2=0

a = 1; b = 2; c = +2;
Δ = b2-4ac
Δ = 22-4·1·2
Δ = -4
Delta is less than zero, so there is no solution for the equation

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